For a causal continuous-time LTI system, where is the ROC relative to its poles?

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Multiple Choice

For a causal continuous-time LTI system, where is the ROC relative to its poles?

Explanation:
For a causal continuous-time LTI system, the impulse response exists only for t ≥ 0, so its Laplace transform converges in a region of the complex plane that must lie to the right of all poles. Each pole contributes a term that behaves like e^{p t}, and for the integral defining the transform to converge as t → ∞, the real part of s must exceed the real part of every pole. This makes the region of convergence a vertical half-plane: all s with Re(s) greater than the largest Re(pole). In other words, the ROC is to the right of the rightmost pole.

For a causal continuous-time LTI system, the impulse response exists only for t ≥ 0, so its Laplace transform converges in a region of the complex plane that must lie to the right of all poles. Each pole contributes a term that behaves like e^{p t}, and for the integral defining the transform to converge as t → ∞, the real part of s must exceed the real part of every pole. This makes the region of convergence a vertical half-plane: all s with Re(s) greater than the largest Re(pole). In other words, the ROC is to the right of the rightmost pole.

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